[FONT="Arial"]Hey guys! I have Calculus problems :( So I am asking all you smart fellows to help me out :D :D
The question is: If e^(-0.1) is computed using a Maclaurin series, then, correct to 3 decimal places, it equals:
A) 0.905
B) 0.950
C) 0.904
D) 0.900
E) 0.949
I used the Lagrange error bound and I discovered that I would only need 2 terms of the series, which I thought was weird :( So I tested it out, and the answer I ended up getting was 0.900. But that's not even three-decimals accurate to the real value of e^(-0.1) :( [/FONT]