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Lan wrote on 2012-09-27 01:19
I have to find the derivitive of y=(2x^2+3x)^3(3x^4+6)^2 If someone can give me the starting point that'd be really helpful :D
I think I have to use chain rule and product rule somewhere but I'm rather stuck. :bow:
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Halfslashed wrote on 2012-09-27 02:45
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Episkey wrote on 2012-09-27 02:47
[S]You would use the chain rule twice.
The first time for (2x^2+3x)^3 and then the second time for (3x^4+6)^2.
If you did that Chain rule correctly - you should get (I believe):
[SPOILER="Spoiler"]3(2x^2+3x)^2 (4x+3) 2(3x^4+6) (12x^3+6)[/SPOILER]
Those are all multiplied by each other. So then it's distributing and foiling from there to get the final answer.
I'm pretty sure my numbers are correct- but I'm basing it off memory. I'm currently in Calc I ... D:[/S]
EDIT:
Or not? I guess since you would use the product rule. And then use chain rule for finding the derivative of f ang g?
Gah. I need to actually think more about this.
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psyal wrote on 2012-09-27 03:33
If you mean (2x^2+3x)^3 * (3x^4+6)^2 , then:
First, considering it's a product of two things, first apply the product rule. You'll be using the chain rule after/with that.