Quote from Jake;1266625:
Pretty sure in the photo that's in circulation this is the only choice that is to be made. When you blow up the colors, this happens:
http://www.color-hex.com/color/808ab6
[Image: http://puu.sh/gftNj/cb1c5ed955.png]
http://www.color-hex.com/color/675034
[Image: http://puu.sh/gftOG/d5842c9b14.png]
I can understand the blue to an extent, but I don't think it's humanly possible to consider the second color as actual black
http://mashable.com/2015/02/26/buy-blue-black-white-gold-dress/
too bad it is actually black lol
it's just a bad photo, that's all
to be more specific, since the entire image is overexposed with yellow lighting, it makes sense that the black parts of the dress are only brown/gold hues, rather than pure black. If you mix yellow with black (in both color addition and subtraction, since black is literally the absence of all color), you're gonna get brown. A photo would actually have to be dark enough to have 0, 0, 0 as a sample... and that image clearly isn't dark enough.
The blue also almost seems entirely desaturated due to the yellow lighting -- as in accordance with color addition, if you mix yellow with blue, you get white. Or in this case, a desaturated blue since the intensity of yellow isn't as strong as the intensity of blue.
So it makes sense why some people are seeing it as white and gold... but judging from the entire photo, the overexposure you can see from the background should indicate that the entire image is overexposed, therefore the colors on the dress are, in reality, darker than they appear to be in the photo. With white and gold being on the light end of the color spectrum, you'd be able to rule that out as a possibility for the /actual/ colors of the dress.